オブジェクトのオーバーロード 関数
creating two methods with the same name won't work for sure (maybe in next versions i hope)
but for now all i could come up with something that looks like overloaded functions from the outside but still makes it a bit difficult for the one who's coding the actual class
as we can see in the code bellow i've used a default value for the $name argument, so when the Test() method is called with no arguments the $name argument is by default passed as NULL (or any value you wanna pass)
<?php
class Test
{
function Test($name=NULL)
{
echo 'Hello, ';
if($name)
{
echo $name.'<br>';
}
else
{
echo 'stranger<br>';
}
}
}
$t1=new Test(); // Output : Hello, stranger
$t2=new Test('Osman Kalache'); // Output : Hello, Osman Kalache
?>
the bad side of this trick is that you have to test your arguments (imagine how many IFs and ELSEs you get if you had just 5 arguments)
but still makes your classes easy to use.
overload
(PHP 4 >= 4.2.0)
overload — クラスのプロパティおよびメソッドに関してオーバーロードを可能にする
説明
void overload
( string $class_name
)
overload() 関数は、 class_name で指定されたクラスのプロパティと メソッドコールをオーバーロードします。
パラメータ
- class_name
-
オーバーロードするクラス名。
返り値
値を返しません。
例
このパートの導入部にある 例 を参照ください。
add a note
User Contributed Notesoverload
osminosm at gmail dot com
22-Jan-2009 05:22
22-Jan-2009 05:22
tim at e2-media dot co dot nz
09-Jun-2008 02:35
09-Jun-2008 02:35
Note that this function is totally pointless in php5. All it does is set up the same behaviour for a php4 class that already exists in php5.